Hi, I have a requirement where i have created a set to list all the users who doesnt have "Display Name". Can anyone help on this.? i have given Display Name not starts with (Display Name,'%'). But still its displaying all the users who have display name.

Hi, There is a blog that describes this very well, you can find it here: http://blogs.dirteam.com/blogs/jorge/archive/2009/11/12/fim-2010-not-not-is-empty-and-not-equal-i-think.aspx Kind regards, Freek Berson http://microsoftplatform.blogspot.com/

Hi, There is a blog that describes this very well, you can find it here: http://blogs.dirteam.com/blogs/jorge/archive/2009/11/12/fim-2010-not-not-is-empty-and-not-equal-i-think.aspx Kind regards, Freek Berson http://microsoftplatform.blogspot.com/

As you can see from Jorge's post the following filter should build a set with all users having a DisplayName /Person[DisplayName != '_$$$_'] The result is correct as long as you do not expect real DisplayNames with the value _$$$_ Unfortuanatly FIM 2010 doesn't support double negotions anymore - something like /Person[not(MyAttribute != '_$$$_')] /Matthias

As you can see from Jorge's post the following filter should build a set with all users having a DisplayName /Person[DisplayName != '_$$$_'] The result is correct as long as you do not expect real DisplayNames with the value _$$$_ Unfortuanatly FIM 2010 doesn't support double negotions anymore - something like /Person[not(MyAttribute != '_$$$_')] /Matthias

As fro Jorge's post the following filter should build a set with all users having a DisplayName /Person[DisplayName != '_$$$_'] The result is correct as long as you do not expect real DisplayNames with the value _$$$_ Unfortuanatly FIM 2010 doesn't support double negotions anymore - something like /Person[not(MyAttribute != '_$$$_')] /Matthias/Matthias

As fro Jorge's post the following filter should build a set with all users having a DisplayName /Person[DisplayName != '_$$$_'] The result is correct as long as you do not expect real DisplayNames with the value _$$$_ Unfortuanatly FIM 2010 doesn't support double negotions anymore - something like /Person[not(MyAttribute != '_$$$_')] /Matthias/Matthias

Any solution is there for this?

Any solution is there for this?

0. User without DisplayName = All Users - Users with DisplayName 1. Create a set containing all users with a valid displayName XPath-Filter: /Person[DisplayName != '_$$$_'] 2. Create a set containg all users expect members of the first set XPath-Filter: /Person[ObjectID != /Set[ObjectID='<ObjectID of the first set>']/ComputedMember] /Matthias

I tried creating a a set like XPath-Filter: /Person[DisplayName != '_$$$_'] Display Name is not '_$$$_' But it displays all the users who have/doesnt have display name. Also when i tried creating the set containing all the users except members of the first set like XPath-Filter: /Person[ObjectID != /Set[ObjectID='<ObjectID of the first set>']/ComputedMember] Also when i tried selecting Resource Id it allows me to pick only the users in FIM but not the set i have created which has the list of display name How to proceed in this case.

Configuring filter rules using the UI may have some limitations. You overcome these limitations the following way: Create a simple Set with a common filter Open the Set, select Advanced View, then Extended Attributes Modify the Filter Attribute to fit your requirements The first set filter attribute should look like: <Filter xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Dialect="http://schemas.microsoft.com/2006/11/XPathFilterDialect" xmlns="http://schemas.xmlsoap.org/ws/2004/09/enumeration">/Person[DisplayName != '_$$$_']</Filter> The second set filter attribute should look like: <Filter xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Dialect="http://schemas.microsoft.com/2006/11/XPathFilterDialect" xmlns="http://schemas.xmlsoap.org/ws/2004/09/enumeration">/Person[ObjectID != /Set[ObjectID='<ObjectID of the first set>']/ComputedMember]</Filter> /Matthias

Thanks for the suggestions. I have tried giving Display Name not starts with % and it displays all the user records which does not have Display Name. It worked fine.

What was your final solution? The two Sets I've described above or did find another solution/Matthias

Ya but in a simple way. I have created a set with user match all conditions. and have given DisplayName not starts with % . It displayed all the users who doesnot have display name. Thanks

Ya but in a simple way. I have created a set with user match all conditions. and have given DisplayName not starts with % . It displayed all the users who doesnot have display name. Thanks