Hi, is there any way for an administrator to know which user has activated his/her Office365 ProPlus?

Currently, I'm deploying Office365 to users using SCCM, so I can know how many user has "installed" Office 365 ProPlus but cannot know activation status.

Office 365 admin protal seems not able to extract the user list who has been activated.

Is there any other way using SCCM or any commands to list up activated users?

Thanks!!

Hi,

Since this issue is related to Office 365 activation management, I recommend you post the question to Office 365 forum:

http://community.office365.com/en-us/f/148.aspx

The reason why we recommend posting appropriately is you will get the most qualified pool of respondents, and other partners who read the forums regularly can either share their knowledge or learn from your interaction with us. Thank you for your understanding.

George Zhao
TechNet Community Support

Hello Hiroki!

You can deploy custom script, which will check results from ospp.vbs /dstatus. Details you can find about this tool at Troubleshooting tips for Office 365 ProPlus.

There is also coming new feature to Office 365 admin center, where "Office 365 ProPlus user activation management allows administrators to view and manage Office 365 ProPlus activations on PCs or Macs directly from the Office 365 Admin Center". If you have First Release not activated, this should deliver this to you faster.

Hello Hiroki!

You can deploy custom script, which will check results from ospp.vbs /dstatus. Details you can find about this tool at Troubleshooting tips for Office 365 ProPlus.

There is also coming new feature to Office 365 admin center, where "Office 365 ProPlus user activation management allows administrators to view and manage Office 365 ProPlus activations on PCs or Macs directly from the Office 365 Admin Center". If you have First Release not activated, this should deliver this to you faster.

• Proposed as answer by George.Zhao CHNMicrosoft contingent staff, Moderator 21 minutes ago

Hi George, I honestly mean, that my reply below is a little more useful to solution.