Certificate Authority
What reasons would you not want to set the option below for user certificates?
Do not automatically re-enroll if a duplicate certificate exists in Active Directory
July 30th, 2012 4:39am
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July 30th, 2012 4:41am
What reasons would you not want to set the option below for user certificates?
Do not automatically re-enroll if a duplicate certificate exists in Active Directory
July 30th, 2012 10:07am
Link to the new thread: http://social.technet.microsoft.com/Forums/en-US/winserversecurity/thread/b1c62dce-ddfa-4ec2-b442-a403e67bd334/#b1c62dce-ddfa-4ec2-b442-a403e67bd334
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July 30th, 2012 11:14am
Hi dwelldon,
actually this is a very good question.
Usually there is no need to publish authentication certificates to AD, so this option would not help here at all.
For EFS and Outlook S/MIME you want publish the encryption certificates so that the sender can encrypt the e-mail. If your user logs on to multiple machines he is getting a new certificate (including private key) if autoenrollment cannot find a certificate
in the Windows profile. In this scenario the user cannot read encrypted data because the data was encrypted to another public key.
I never had a real world scenario for publishing certs to AD and not activating this option.
Regards, Lutz
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July 30th, 2012 12:15pm
Hi Dwelldon,
Thanks for posting in Microsoft TechNet forums.
If the Do not automatically reenroll if a duplicate certificate exists in Active Directory is enabled, autoenrollment will not enroll a user for the certificate template, even if a certificate does not exist in the users MY store. Active Directory is queried
and determines if the user should be enrolled. This is an extremely valuable feature for users who do not have roaming profiles and log on to multiple machines. Without this setting and without roaming profiles, the user will automatically be enrolled on every
machine that is logged on to (including servers).
Here are two articles for your reference:
Configure Certificate Publishing in Active Directory Domain Services
http://technet.microsoft.com/en-us/library/cc730861.aspx
How Autoenrollment Works
http://technet.microsoft.com/en-us/library/cc787781(v=ws.10).aspx
Regards
Kevin
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July 30th, 2012 10:47pm
Hi Dwelldon,
Thanks for posting in Microsoft TechNet forums.
If the Do not automatically reenroll if a duplicate certificate exists in Active Directory is enabled, autoenrollment will not enroll a user for the certificate template, even if a certificate does not exist in the users MY store. Active Directory is queried
and determines if the user should be enrolled. This is an extremely valuable feature for users who do not have roaming profiles and log on to multiple machines. Without this setting and without roaming profiles, the user will automatically be enrolled on every
machine that is logged on to (including servers).
Here are two articles for your reference:
Configure Certificate Publishing in Active Directory Domain Services
http://technet.microsoft.com/en-us/library/cc730861.aspx
How Autoenrollment Works
http://technet.microsoft.com/en-us/library/cc787781(v=ws.10).aspx
Regards
Kevin
TechNet Subscriber Support
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TechNet Subscription
user and have any feedback on our support quality, please send your feedback
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July 30th, 2012 10:52pm
Many thanks for the replies, I will have a read of the articles.
July 31st, 2012 8:38am
Hi Dwelldon,
Just check to see if you would like further assistance regarding this issue. Please feel free to let us know if there is anything else we can help.
Have a nice day.
Regards
Kevin
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August 2nd, 2012 10:57pm
Hi Dwelldon,
As this thread has been quiet for a while, we assume that the issue has been resolved. At this time, we will mark it as Answered as the information should be helpful for many similar scenarios. If the issue still persists, please feel free to reply this post
directly so we will be notified to follow it up. You can also choose to unmark the answer as you wish.
BTW, wed love to hear your feedback about the solution. By sharing your experience you can help other community members facing similar problems. Thanks for your understanding and efforts.
Best Regards
Kevin
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August 5th, 2012 10:24pm


